VSDs contain a converter to transform AC to DC, a filter section to smooth out the waveform, and an inverter to provide an AC output.
The input section of the drive is the converter. It contains six diodes, arranged in an electrical bridge. These diodes convert AC power to DC power. The diodes actually reconstruct the negative halves of the waveform onto the positive half. In a 460-V unit, you'd measure an average DC bus voltage of about 650V to 680V. You can calculate this as line voltage times 1.414.
The next section,"the DC bus section,"sees a fixed DC voltage and filters and smoothes out the waveform. The inductor, L, and the capacitor, C, together remove any AC component of the DC waveform. The smoother the DC waveform is, the cleaner the output waveform from the drive.
The DC bus feeds the final section of the drive, the inverter. It inverts the DC voltage back to AC, but provides a variable voltage and frequency output. How does it do this? That depends on the kind of power devices your drive uses. If you have many silicon-controlled-rectifier (SCR) based drives in your facility (Box, p.42). Bipolar transistor technology began superseding SCRs in drives in the mid-1970s, and, in turn, gave way in the early 1990s to Insulated Gate Bipolar Transistor (IGBT) technology.
Switching Bus With IGBTs
Today's inverters use IGBTs to switch the DC bus on and off at specific intervals. In doing so, the inverter actually creates a variable AC voltage and frequency output.As shown in Fig. 7, the output of the drive doesn't provide an exact replica of the AC-input sine waveform. Instead, it provides voltage pulses that are at a constant magnitude. The drive's control board signals the power device's control circuits to turn "on" the waveform positive half or negative half of the power device. This alternating of positive and negative switches recreates the 3-phase output.
Figure 7. Voltage and Current of Output Waveform